6p^2-18=3p

Solution for 6p^2-18=3p equation:

6p^2-18=3p

We move all terms to the left:

6p^2-18-(3p)=0

a = 6; b = -3; c = -18;
Δ = b2-4ac
Δ = -32-4·6·(-18)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-21}{2*6}=\frac{-18}{12}
=-1+1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+21}{2*6}=\frac{24}{12}
=2
$